8x^2-200x+625=0

Solution for 8x^2-200x+625=0 equation:

8x^2-200x+625=0

a = 8; b = -200; c = +625;
Δ = b2-4ac
Δ = -2002-4·8·625
Δ = 20000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{20000}=\sqrt{10000*2}=\sqrt{10000}*\sqrt{2}=100\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-200)-100\sqrt{2}}{2*8}=\frac{200-100\sqrt{2}}{16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-200)+100\sqrt{2}}{2*8}=\frac{200+100\sqrt{2}}{16}
$